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2x^2-44x+240=0
a = 2; b = -44; c = +240;
Δ = b2-4ac
Δ = -442-4·2·240
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-4}{2*2}=\frac{40}{4} =10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+4}{2*2}=\frac{48}{4} =12 $
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